Answer by Qmechanic for Time-ordered product vs path integral
Well, in a nutshell the issue is the following. Recall that the path integral formulation [with a $\mathbb{Z}_2$-graded (super)commutative integrand] is derived from the non-commutative operator...
View ArticleTime-ordered product vs path integral
Suppose we have the Green function$$G(k) \equiv \tag 1\int d^4x e^{ikx}\langle 0| T\left(\partial^{x}_{\mu}A^{\mu}(x)B(0)\right)|0\rangle ,$$which in path integral approach is equal to $$\tag 2 G(k)...
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